Quadratic Equation
Quadratic Equations — JEE Mathematics Complete Guide
Standard form, discriminant and roots, Vieta, vertex and range, inequalities, parameter questions, classic patterns, pitfalls — plus an interactive graph. Fully blogger‑friendly with proper equation rendering.
JEE syllabus coverage
- Standard form: $ax^2+bx+c=0,\; a\ne 0$
- Discriminant & roots: $D=b^2-4ac$; nature of roots; quadratic formula
- Vieta’s relations: sum/product of roots; forming equations
- Vertex, axis, range: completing square; min/max; graph
- Inequalities: sign chart using roots and $a$
- Parameter questions: conditions on $k$ for roots/restrictions
Core results
Quadratic formula and nature
- $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$
- $D>0$: two distinct real; $D=0$: equal real; $D<0$: non‑real conjugates
Vieta’s relations
- If roots are $\alpha,\beta$: $\alpha+\beta=-\dfrac{b}{a}$, $\alpha\beta=\dfrac{c}{a}$
- Equation from roots (leading coefficient $a$): $a\left(x^2-(\alpha+\beta)x+\alpha\beta\right)=0$
Vertex and range
- $ax^2+bx+c=a\left(x+\dfrac{b}{2a}\right)^2-\dfrac{D}{4a}$
- Vertex: $\left(-\dfrac{b}{2a},-\dfrac{D}{4a}\right)$; Range: $a>0\Rightarrow [y_v,\infty)$, $a<0\Rightarrow (-\infty,y_v]$
Inequalities (exam‑style)
- $a>0$ opens up (U); $a<0$ opens down (∩).
- $D>0$, roots $x_1
0$: $f(x)\ge 0$ on $(-\infty,x_1]\cup[x_2,\infty)$, and $f(x)\le 0$ on $[x_1,x_2]$. Reverse for $a<0$. - $D=0$: touches x‑axis at $x_v$. If $a>0$: $f(x)\ge 0$ for all $x$; if $a<0$: $f(x)\le 0$ for all $x$.
- $D<0$: no real roots. If $a>0$: $f(x)>0$; if $a<0$: $f(x)<0$.
For rational inequalities, exclude where denominator $=0$ and apply sign chart by intervals.
Parameter (k) frames
Reality/equality of roots
- Given $ax^2+bx+c(k)=0$: define $D(k)=b^2-4a\,c(k)$. Real roots $\Leftrightarrow D(k)\ge 0$; equal roots $\Leftrightarrow D(k)=0$.
Both roots on one side of $m$
- Let $g(x)=f(x+m)=ax^2+Bx+C$, $B=b+2am,\; C=am^2+bm+c$.
- For $a>0$: both $>m \Leftrightarrow -\dfrac{B}{a}>0$ and $\dfrac{C}{a}>0$; both $
0$.
Interactive quadratic graph
Axes have arrowheads; vertex (•), roots (if real), axis of symmetry (dashed), and shaded inequality regions.
Formula crib sheet
| Result | Formula | Use |
|---|---|---|
| Quadratic formula | $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$ | Exact roots |
| Discriminant | $D=b^2-4ac$ | Nature of roots |
| Vieta | $\alpha+\beta=-\dfrac{b}{a},\;\alpha\beta=\dfrac{c}{a}$ | Forming equations |
| Vertex | $\left(-\dfrac{b}{2a},-\dfrac{D}{4a}\right)$ | Range, extrema |
| Completed square | $a\left(x+\dfrac{b}{2a}\right)^2-\dfrac{D}{4a}$ | Graph/transform |
Practice set (quick keys)
- Minimum of $2x^2-8x+7$.
Key: $x_v=2$, $y_{\min}=-\dfrac{D}{4a}=-1$.
- Find $k$ so $x^2-4x+k=0$ has equal roots.
Key: $D=16-4k=0\Rightarrow k=4$.
- Solve $x^2-5x+6\ge 0$.
Key: roots $2,3$; solution $(-\infty,2]\cup[3,\infty)$.
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